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2 years ago

3.PS-15

Mathematics

1 answer:

lianna [129]2 years ago

3 0

Answer:

Step-by-step explanation:

3.PS-15

Challenge The members of the city cultural center have decided to put on a play once a night for a

week. Their auditorium holds 500 people. By selling tickets, the members would like to raise $2,350

every night to cover all expenses. Let d represent the number of adult tickets sold at $6.50. Lets

represent the number of student tickets sold at $3.50 each. If all 500 seats are filled for a

performance, how many of each type of ticket must have been sold for the members to raise exactly

$2,350? At one performance there were three times as many student tickets sold as adult tickets. If

there were 400 tickets sold at that performance, how much below the goal of $2,350 did ticket sales

fall?

The members sold

adult tickets and

student tickets.

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Pls help me on this!

Zigmanuir [339]

Answer:

4 45/100 Keep simplifying it. You can do it!

Step-by-step explanation:

4 is the whole. 45 is out of 100

7 0

3 years ago

45.6/109.2 = x/115<br><br> Is x, 48.02?

MAXImum [283]

Yes correct x is 48.02 here is why.

simplify 45.6/109.2 to 0.417582

multiply both sides by 115

simplify 0.417582 x 115 to 48.021978

switch sides

Answer: x = 48.021978

4 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago

Ken earned 128 from his part time summer job

Naya [18.7K]

You are missing part of the question

3 0

3 years ago

Help Will give crown!!

Vlada [557]

Answer:

the answer is 6

Step-by-step explanation:

if u look 2.5 gives u 3 so 5 would give u 6

6 0

3 years ago