Question

How to solve (x+2)^3/4=27

Answer 1

$\frac{(x + 2)^{3}}{4} = 27$
$4(\frac{(x + 2)^{3}}{4}) = 4(27)$ Multiply it by 4 on each side.
$(x^{2} + 2)^{3} = 108$ 
$\sqrt[3]{(x^{2} + 2)^{3}} = \sqrt[3]{108}$ Find the cube root of each.
$x^{2} + 2 \approx 4.76$
$x^{2} \approx 2.76$ Subtract 2 from each side.
$\sqrt{x^{2}} \approx \sqrt{2.76}$ Find the square root of each.
$x \approx \±2.76$