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xeze [42]
3 years ago
14

How to solve (x+2)^3/4=27

Mathematics
1 answer:
faust18 [17]3 years ago
5 0
\frac{(x + 2)^{3}}{4} = 27
4(\frac{(x + 2)^{3}}{4}) = 4(27) Multiply it by 4 on each side.
(x^{2} + 2)^{3} = 108 
\sqrt[3]{(x^{2} + 2)^{3}} = \sqrt[3]{108} Find the cube root of each.
x^{2} + 2 \approx 4.76
x^{2} \approx 2.76 Subtract 2 from each side.
\sqrt{x^{2}} \approx \sqrt{2.76} Find the square root of each.
x \approx \±2.76
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