WANT FREE 20 POINTS + BRAINLIEST? ANSWER THIS GEOMETRY QUESTION CORRECTLY AND I GOT YOU :)
2 answers:
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Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 2x + y = - 5 into this form by subtracting 2x from both sides
y = - 2x - 5 ← in slope- intercept form
with slope m = - 2
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= -
, hence
y = x + c ← is the partial equation of the perpendicular line
To find c substitute (- 1, - 2) into the partial equation
- 2 = - + c ⇒ c = -
y = x -
← equation in slope- intercept form
9514 1404 393
Answer:
a) the degree of the polynomial
b) count the x-intercepts, with attention to multiplicity
Step-by-step explanation:
The Fundamental Theorem of Algebra tells you the number of zeros of a polynomial is equal to the degree of the polynomial. That is, for some polynomial p(x), the number of solutions to p(x)=0 will be the degree of p.
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On a graph, a real zero of the polynomial will be an x-intercept. The "multiplicity" of a zero is the degree of the factor giving rise to that zero. When the multiplicity is even, the graph does not cross the x-axis at the x-intercept. The greater the multiplicity, the "flatter" the graph is at the x-intercept.
If all solutions (zeros) are distinct, then the number of real solutions can be found by counting the number of x-intercepts of the graph.
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By way of illustration, the attached graph is of a 6th-degree polynomial with 6 real zeros. From left to right, they are -1 (multiplicity 1), 1 (multiplicity 2), 4 (multiplicity 3). The higher multiplicities are intended to show the flattening that occurs at the x-intercept, and the fact that the graph does not cross the x-axis where the multiplicity is even.
