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Nikolay [14]
3 years ago
8

Six identical coins are tossed. How many possible arrangements of the coins include three heads and three tails?​

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

The possible arrangement= 18 ways

Step-by-step explanation:

Six identical coin are tossed.

Coin has only a tail and a head.

In how many possible ways can the arrangement be 3 head and 3 tail.

The possible arrangement= (3! * 3!)/2

The reason for dividing by two because coin has two face.

The possible arrangement= (3! * 3!)/2

The possible arrangement=( 6*6)/2

The possible arrangement= 36/2

The possible arrangement= 18 ways

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Step-by-step explanation:

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Ok, I did this unit a little while ago but I think I solved it:

Hyp = 16

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Step-by-step explanation:

You were on the right track, with the sin = opp/hyp, you just have to follow the equation given. So if sin = 8/16, then opp = 8 and hyp = 16 due to the transitive theorem.

Now you have to use the pythagorean theorem for the third side (adj), so:

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The answer would be around 13.856 (round to what's required.)

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