Answer:
$848
Step-by-step explanation:
Calculation for the cost of this familiy's clothing in 1991
First step is to calculate the amount that is increase per year
Increase per year= ($1000-$620)/(1995-1985)
Increase per year= 380/10
Increase per year= $38
Now let y be :38*x + $620 and let x be 6 years (1991-1985)
Second step is to calculate the cost of the clothing in 1991
y = 38*6 + 620
y=228+620
y = $848
Therefore the cost of this familiy's clothing in 1991 will be $848
Divide 35423 by 15 and round the answer down to a whole number, then you get 2361. If you subtract 15*2361 from 35423 you get the remainder 8. So answer C is correct.
Answer:
1
Step-by-step explanation:
1 because it 1 and I know it one I need help 1
Answer:
Sum of money invested in corporate bonds = 30,000
Step-by-step explanation:
Total sum = 40,000
The rate of interest for corporate bonds = 10 % = 0.1
The rate of interest for municipal bonds = 6 % = 0.06
Total interest = 3600
Let sum of money invested in corporate bonds = x
The sum of money invested in municipal bonds = 40000 - x
× 0.1 × 1 + (
) × 0.06 × 1 = 3600
(0.1- 0.06) + 2400 = 3600
0.04 = 1200
= 30,000
Since x = sum of money invested in corporate bonds
So sum of money invested in corporate bonds = 30000
