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kozerog [31]
3 years ago
6

If 5 friends want to share 1.25 of a pizza evenly,how much pizza would each person get?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
8 0
1.25 divided by 5. This is 0.25 or 1/4 of the pizza.
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Write an equation that will help you solve the word problem below. Myles charges $10.50 per hour working as a babysitter and cha
olya-2409 [2.1K]

Answer:

the total cost would be $89.50

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The length of one strip of paper is 1 whole unit.Fold two strips of paper in half.Open the strips and place them ent end .How ma
Harman [31]

Answer:

The total number of halves is 4 and the lines are considered as 1/4, 1/2 and 3/4.

Step-by-step explanation:

When both the strips are placed end to end the total number of halves is 4, 2 for each of the paper strips. Lines are as indicated in the figure attached.

5 0
3 years ago
If f ( x ) f(x) is an exponential function where f ( − 3.5 ) = 25 f(−3.5)=25 and f ( 6 ) = 33 f(6)=33, then find the value of f
gavmur [86]

Given:

f(x) is an exponential function.

f(-3.5)=25, f(6)=33

To find:

The value of f(6.5).

Solution:

Let the exponential function is

f(x)=ab^x         ...(i)

Where, a is the initial value and b is the growth factor.

We have, f(-3.5)=25. So, put x=-3.5 and f(x)=25 in (i).

25=ab^{-3.5}         ...(ii)

We have, f(6)=33. So, put x=6 and f(x)=33 in (i).

33=ab^{6}         ...(iii)

On dividing (iii) by (ii), we get

\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}

1.32=b^{9.5}

(1.32)^{\frac{1}{9.5}}=b

1.0296556=b

b\approx 1.03

Putting b=1.03 in (iii), we get

33=a(1.03)^{6}

33=a(1.194)

\dfrac{33}{1.194}=a

a\approx 27.63

Putting a=27.63 and b=1.03 in (i), we get

f(x)=27.63(1.03)^x

Therefore, the required exponential function is f(x)=27.63(1.03)^x.

4 0
3 years ago
Find tfind the distance between each pair of points (4,6 ) (-1, 8)
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The answer is 8.06. Follow these steps. This is an example.

a2+b2=c2

9^2+12^2=c^2

81+144=c^2

225 =c^2

Since 225 = c2, take the square root of both sides to solve for c.


225=c^2

So the answer is

±15




6 0
3 years ago
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An automobile dealer had 288 cars and trucks in stock during the month. He must pay an inventory fee of 52 per car and $5 per tr
Aleonysh [2.5K]

For the given conditions, we won’t get a practical solution.

<u>Solution:</u>

Given, An automobile dealer had 288 cars and trucks in stock during the month.  

He must pay an inventory fee of 52 per car and $5 per truck.  

He paid $849 for inventory foes.  

We have to find how many cars and Trucks did he have during the month?

Now, let the number of trucks be n, then number of cars will be 288 – n

And, according to given information,

\begin{array}{l}{5 \times n+52 \times(288-n)=849} \\\\ {\rightarrow 5 n+52 \times 288-52 n=849} \\\\ {\rightarrow 52 n-5 n=14976-849} \\\\ {\rightarrow 47 n=14127} \\\\ {\rightarrow n=300.57}\end{array}

Here we got n > number of cars and trucks, which is practically impossible.  

Hence, for the given conditions, we won’t get a practical solution

8 0
3 years ago
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