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MakcuM [25]
3 years ago
8

Find the area of the following composite figures Open the picture Thank youuuuu

Mathematics
1 answer:
ANEK [815]3 years ago
6 0

I like area questions.

On the left we have a triangle, base apparently 9 cm, height 7 cm.

In the middle it's a 3 cm by 9 cm rectangle.

Then it's a parallelogram, base 9.  We have to figure out the height; it must be 16 - 7 - 3 = 6 cm.

Adding up the areas,

A = (1/2) 9×7 + 3×9 + 6×9 = 112.5 sq cm

Answer: 112.5 sq cm

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(a) Use a linear approximation to estimate f(0.9) and f(1.1). f(0.9) ≈ f(1.1) ≈ (b) Are your estimates in part (a) too large or
olasank [31]

Answer:

(Missing part of the question is attached)

L(x)=2x+3

Estimates are too large.

Step-by-step explanation:

Suppose the only information we know about the function is:

f(1)=5

where the graph of its derivative is shown in the attachment

<h3>(a)</h3>

If the function f\\ is differentiable at point x=1 , the tangent line to the graph of f at 1 is given by the equation:

y=f(1) +f'(1)(x-1)

So we call the linear function:

L(x)=f(1) +f'(1)(x-1)

We know the f(1)=5 as it is given in the question, and f'(1)=2 from the graph attached. Substitute in the equation of L(x).

L(x)=5+2(x-1)\\L(x)=5+2x-2\\L(x)=2x+3\\

<h3>(b)</h3>

At x=1,  f'(x) is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve f. Thus, The estimates are too large.

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3 years ago
What function can be used to model data pairs that have a common ratio?
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Correct answer is C.

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2=\frac{4}{2} = \frac{8}{4} = \frac{16}{8} = \frac{32}{16} =...

y=2^x
4 0
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Each tree in the orchard had exactly 118 apples on it. The number of apples in the whole orchard was 2,242. How many apple trees
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That the panda approximately is about 35 months old, and is approximately weighs 82 kilograms
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2 years ago
joe has a piggy bank with $8.90 split upon nickels, dimes, and quarters. The piggy bank contains 76 coins in all. The number of
kozerog [31]

Answer:

There are 38 dimes, 22 nickels and 16 quarters.

Step-by-step explanation:

Let n, d and q represent the # of nickels, dimes and quarters respectively.

Then n + d + q = 76

The value of a nickel is $0.05; that of a dime is $0.10, and that of a quarter is $0.25.

Thus, the value of n nickels is $0.05n (and so on).

The total value of the coins is $0.05n + $0.10d + $0.25q = $8.90.

d = n + q allows us to eliminate d.

First, n + d + q = 76 becomes n + (n + q) + q = 76, and second:

$0.05n + $0.10(n + q) + $0.25q = $8.90.  Here we have succeeded in eliminating d from two different equations, and now we have these two different equations in two unknowns (n and q), which is solvable.

Simplifying both equations, we get:

2n + 2q = 76 and

5n + 10n + 10q + 25q = 890, or 15n + 35q = 890

Let's use the substitution method of solving linear equations:

Rewrite 2n  + 2q = 76 as n + q = 38, or n = 38 - q.  Substituting this result into the second equation, we get:

15(38 - q) + 35 q = 890, or

  570 - 15q + 35q = 890, or

   570 + 20 q = 890.  Then 20q = 890 - 570 = 320, and q = 320/20 = 16.

There are 16 quarters.  Thus, the number of nickels is n = 38 - 16 = 22.

Finally, since n + d + q = 76, 22 + d + 16 = 76, or:

22 + d = 60, or d = 60 - 22 = 38.

There are 38 dimes, 22 nickels and 16 quarters.

4 0
3 years ago
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