1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
7

A data set includes 104body temperatures of healthy adult humans having a mean of 98.7degreesFand a standard deviation of 0.66de

greesF.Construct a 99​%confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6degreesFas the mean body​ temperature?
Mathematics
1 answer:
muminat3 years ago
3 0

Answer:

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 104 - 1 = 103

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 103 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.624

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.624\frac{0.66}{\sqrt{104}} = 0.17

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.7 - 0.17 = 98.53ºF.

The upper end of the interval is the sample mean added to M. So it is 98.7 + 0.17 = 98.87 ºF.

The 99​% confidence interval estimate of the mean body temperature of all healthy humans is between 98.53ºF and 98.87 ºF. 98.6ºF is part of the interval, so the sample suggests that the use of 98.6ºF as the mean body​ temperature is correct.

You might be interested in
I don't get this I really need help to understand this "/
Alisiya [41]
I don't either it is quite hard to be fair
4 0
3 years ago
What is the y-value of point A?
PSYCHO15rus [73]

Answer: 1

The full term is (6,1)

6 0
3 years ago
Read 2 more answers
Please help (Its multiple choice)
artcher [175]

Step-by-step explanation:

-5(4a) = (-5a)4

(By commutative property of multiplication)

4 0
3 years ago
Read 2 more answers
Which of these prices is lower than 5 for $3.00
Serga [27]

Where's the options?

7 0
3 years ago
PLEASE SOMEONE TO HELP ME WHAT ARE THE CORRECT ANSWERS AND IM GIVING BRAINLY
GrogVix [38]

Answer:

10 times greater

Step-by-step explanation:

When you write these as numbers, you get:

800,000,000 (8 hundred million place)

80,000,000 (8 ten million place)

Then divide the greater number by the less number:

800,000,000/800,000,00

make this easier by eliminating 0's:

80<u>0,000,000</u>/8<u>0,000,000</u>

80/8

10

10 times greater is your answer

Hope this helps!

4 0
3 years ago
Read 2 more answers
Other questions:
  • At school barbecue 3 times as many hot dogs were served as Hamburgers. if there were 124
    15·2 answers
  • 48 &gt; 7m - 8 what is m?
    13·2 answers
  • Please help with 1 Math question!!!
    8·1 answer
  • Find tan Ø, given that sin Ø = - 4/5 and cos Ø&gt;0.
    10·1 answer
  • Elainas old bicycle had tires with a 12-inch diameter her new bicycle had tires with a 16-inch diameter what is the difference i
    11·1 answer
  • How do find Herons formula?
    13·1 answer
  • Sal bought a house for 78,524.60 Twelve years later he sold the house for 2 2/3 times as much. What was the sale price of the ho
    13·1 answer
  • This is statistics. Please answer fast
    10·1 answer
  • Mr. Santos purchased pizza and soda. Each pizza cost $14.50. He spent $127 on the soda. If he spent $315.50, use the equation 14
    9·1 answer
  • 234565335364 - 585257056894
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!