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iris [78.8K]
3 years ago
11

What is the equation of the line perpendicular to y=2/3x+1 that passes through the point (12, -6)?

Mathematics
1 answer:
bixtya [17]3 years ago
5 0

Answer:

y= -3/2x + 12

Step-by-step explanation:

When finding a perpendicular line you take your slope and make it the opposite (flip it and change the sign).

Slope originally=2/3

New slope= -3/2

Next we will use the point slope equation

y-y1=m(x-x1)

y1=y value

m=slope

x1=x value

y--6= -3/2(x-12)  Since you have y minus negative 6 you get to change it to y+6

y+6= -3/2(x-12)  Now distribute your slope to both terms inside the parenthesis.

y+6= -3/2(x) -3/2(-12)

y+6= -3/2x +18    Finally subtract 6 from both sides.

  -6             -6

y= -3/2x + 12

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Two similar circles are shown. The circumference of the larger circle, with radius OB, is 3 times the circumference of the small
zheka24 [161]

Answer:

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Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

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Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

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The radius of circle B is: OB = x

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The circumference of circle A will be:

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replacing the equations for the circumferences, we get:

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