All categories

2 years ago

How many times greater is the value 4 in 640,070 than the value of the 4 in 64,070

1 answer:

7 0

How many times greater is the value 4 in 640,070 than the value of the 4 in 64,070

its 10.000 greater :)

hope this heled

You might be interested in

Could someone help me plz i know it's easy one but i couldn't do it

Luden [163]

1. is 5 seconds
2. would be about 105 because is goes a tiny bit over 100

5 0

3 years ago

Factor the polynomial: -2x3 - 4x2 - 6x

larisa [96]

Answer:

For a polynomial of the form ax2+bx+c a x 2 + b x + c , rewrite the middle term as a sum of two terms whose product is a⋅c=2⋅−2=−4 a ⋅ c = 2 ⋅ - 2 = - 4 and whose sum is b=−3 b = - 3 . Factor −3 - 3 out of −3x - 3 x .

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Algebra question<br>1/8m = 6 to find m

coldgirl [10]

1/8 m = 6
m = 48. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)

5 0

2 years ago

Read 2 more answers

Prove that H c G is a normal subgroup if and only if every left coset is a right coset, i.e., aH = Ha for all a e G

Kaylis [27]

$\Rightarrow$

Suppose first that $H\subset G$ is a normal subgroup. Then by definition we must have for all $a\in H$ , $xax^{-1} \in H$ for every $x\in G$ . Let $a\in G$ and choose $(ab)\in aH$ ( $b\in H$ ). By hypothesis we have $aba^{-1} =abbb^{-1}a^{-1}=(ab)b(ab)^{-1} \in H$ , i.e. $aba^{-1}=c$ for some $c\in H$ , thus $ab=ca \in Ha$ . So we have $aH\subset Ha$ . You can prove $Ha\subset aH$ in the same way.

$\Leftarrow$

Suppose $aH=Ha$ for all $a\in G$ . Let $h\in H$ , we have to prove $aha^{-1} \in H$ for every $a\in G$ . So, let $a\in G$ . We have that $ha^{-1} =a^{-1}h'$ for some $h'\in H$ (by the hypothesis). hence we have $aha^{-1}=h' \in H$ . Because $a$ was chosen arbitrarily we have the desired .

5 0

2 years ago

What is 100 in exponential form?

Thepotemich [5.8K]

10 • 10=
Is 10^2
In exponential form

3 0

3 years ago