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enyata [817]
3 years ago
15

Factor the expression 4x + 32. Explain each step you take in the process.

Mathematics
2 answers:
irinina [24]3 years ago
4 0

Step-by-step explanation:

1. What the GCF

the GCF is 4

4(x + 8)

2. divide by 4

4(x+8) is the solution

laiz [17]3 years ago
3 0

Answer:

The GCF of 4x and 32 is 4, so the first step is to divide each term by 4. The quotients are x and 8. The factored expression will be 4(x + 8).

Step-by-step explanation:

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The discriminate of a quadratic is given as b² - 4ac is equal to 0. Select the best description below.
zzz [600]

Answer:

2) the quadratic has one x intercept

Step-by-step explanation:

D = 0 => has twin quadratics as one x intercept

8 0
2 years ago
Find the solution for this inequality<br> -3x + 5 &lt; 5
n200080 [17]

Answer:

2

Step-by-step explanation:

-3x+5 = 2<5

two less than 5

6 0
3 years ago
In which expression does g have a coefficient of 8 <br> 8g <br> 8 + g <br> g - 8 <br> g/8
belka [17]

Answer:

8g

Step-by-step explanation:

In 8g, g has the coefficient 8:  we multiply g by 8.

3 0
3 years ago
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What is the slope of the line that passes through (3,-7) and (-1,1)
mafiozo [28]

the slope would be the change in Y over the change in X,

-7-1= -8, 3-(-1)= 4, -8/4 or -2 is the slope

3 0
3 years ago
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If E F = 7 , A C = 16 , and A F = 9
Vilka [71]

Answers:

CB = 14

GF = 8

FB = 9

EF is parallel to CB

====================================

Explanations:

Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14

For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.

FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length

EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.

8 0
3 years ago
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