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BARSIC [14]
3 years ago
5

Find the 8th term for the series 2, 8, 32, 128, … A. 8192 B. 16384 C. 6784 D. 32768

Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:32,768

2*4=8*4=32*4=128

So we have to multiply by 4

128*4=512 5th term

512*4=2048 6th term

2048*4=8192 7th term

8192*4=32768 last term

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PLZZZ HELP ME I AM FAILING THIS CLLASS> I NEED THE CORRECT ANSWERS THANKYOU!!! I WILL GIVE BRAINLIEST? what doe X...Y...N equ
Elan Coil [88]

Answer:

x = 11

y = 2

n = 4

Step-by-step explanation:

Three equations

Look for x

Look for y

Look for n

__________________

Note that all of these are questions can be answered through isolating the variable.

Let's start with x :

Get x alone :

2(x + 5) = 3x + 1

Distribute :

(2(x) + 2(5))

2x + 10 = 3x - 1

Add 1 to both sides of the equation :

2x + 11 = 3x

Subtract 2x from both sides :

11 = x

x = 11

Next is y :

Isolate y :

3y - 4 = 6 - 2y

Add 4 to both sides :

3y = 10 - 2y

Add 2y to both sides :

5y = 10

Divide 5 from both sides to get y by itself :

y = 2

Lastly is n :

Isolate n :

3(n + 2) = 9(6 - n)

Distribute :

(3(n) + 3(2)) = (9(6) - 9(n))

3n + 6 = 54 - 9n

Subtract 54 from both sides :

3n - 48 = -9n

Subtract 3n from both sides :

-48 = -12n

-12n = -48

Divide -12 from both sides :

n = 4

8 0
3 years ago
What is the sum of the first 5 terms of this geometric series? Use . -4 + 12 + (-36) + ⋯
yKpoI14uk [10]

Answer:

The sum of the first 5 terms is -244

Step-by-step explanation:

To calculate the sum of the geometric series, we need the first term, the common ratio and the number of terms we would like to sum.

The first term here is -4

The common ratio is T2/T1 or T3/T2 = 12/-4 = -3

number of terms n = 5

The formula to use is;

Sn = a(1-r^n)/(1-r)

Plugging these values, we have;

Sn = -4(1-(-3)^5)/(1-(-3))

Sn = -4(1+243)/4 = -1(244) = -244

7 0
3 years ago
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My name is Ann [436]

Answer:

(5,2)

Maximum

5

Step-by-step explanation:

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Answer: 300

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