Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
Lets try to solve out the problem,
Length = 3x-1
Width = x+1
Perimeter = 2(l+b)
Area = l*b
Perimeter= 2 (3x-1 + x+1)
P= 8x
Area = (3x-1) (x+1)
=> 3x(x+1) -1 (x+1)
=> 3x^2 + 3x -x -1
=> 3x^2 + 2x -1.
Hence Perimeter of rectangle is 8x and Area is 3x^2 + 2x -1..
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Answer:
y=3x+1
Step-by-step explanation:
A parallel line has the same slope as the other line.
y=mx+b, m is the slope
Thus in y=3x+1, m =3
y = 3x + b
plug in points (1, 4) to determine b
4 = 3(1) + b
4 = 3 + b
subtract 3 on both sides
4 - 3 = b
b = 1
y = 3x + 1
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Answer:
1.25
Step-by-step explanation:
8/9+6/9 equals 14/9 or 1 and 5/9
