Solution for x^2+5x=150 equation:
<span>Simplifying
x2 + 5x = 150
Reorder the terms:
5x + x2 = 150
Solving
5x + x2 = 150
Solving for variable 'x'.
Reorder the terms:
-150 + 5x + x2 = 150 + -150
Combine like terms: 150 + -150 = 0
-150 + 5x + x2 = 0
Factor a trinomial.
(-15 + -1x)(10 + -1x) = 0
Subproblem 1Set the factor '(-15 + -1x)' equal to zero and attempt to solve:
Simplifying
-15 + -1x = 0
Solving
-15 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '15' to each side of the equation.
-15 + 15 + -1x = 0 + 15
Combine like terms: -15 + 15 = 0
0 + -1x = 0 + 15
-1x = 0 + 15
Combine like terms: 0 + 15 = 15
-1x = 15
Divide each side by '-1'.
x = -15
Simplifying
x = -15
Subproblem 2Set the factor '(10 + -1x)' equal to zero and attempt to solve:
Simplifying
10 + -1x = 0
Solving
10 + -1x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10
Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10
Combine like terms: 0 + -10 = -10
-1x = -10
Divide each side by '-1'.
x = 10
Simplifying
x = 10Solutionx = {-15, 10}</span>
Y=mx+b
b represents your y-intercept
mx represents your slope
Answer:
$25000
Step-by-step explanation:
If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.
$10,000 = 0.40 × cost
$10,000/0.40 = cost = $25,000
The acquisition cost of the equipment was $25,000.
1/3 of an hour = 20 minutes
8 hours = 480 minutes
So to find the number of periods we divide 480 by 20. Answer is 24
