Distributive property
a(b+c)+ab+ac
a(b-c)=ab-ac
(6z^2-4z+1)(8-3z)
move for nicety
(8-3z)(6z^2-4z+1)
distribute
8(6z^2-4z+1)-3z(6z^2-4z+1)=
48z^2-32z+8-18z^3+12z^2-3z=
-18z^3+48z^2+12z^2-32z-3z+8=
-18z^3+60z-35z+8
Answer:
Step-by-step explanation:
Ray HK is an angle bisector, which means that it cuts the angle exactly in half. So half of GHI is 60. If GHK is 3x + 48, and that is half of angle GHI. then
3x + 48 = 60 and
3x = 12 so
x = 4
Answer : The correct option is 
Step-by-step explanation :
According to the BODMAS rule, when the expression contains brackets open ((), {}, []) we have to first simplify the bracket followed by of (powers and roots etc.) and then we have to solve the division, multiplication, addition and subtraction from left to right order (respectively).
The given expression is:
![[\frac{(2a^{-3}b^4)^2}{(3a^5b)^{-2}}]^{-1}](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%7B%283a%5E5b%29%5E%7B-2%7D%7D%5D%5E%7B-1%7D)
![=[\frac{(3a^5b)^{-2}}{(2a^{-3}b^4)^2}]^{1}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B%283a%5E5b%29%5E%7B-2%7D%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D%5E%7B1%7D)
![=[\frac{1}{(3a^5b)^{2}}\times \frac{1}{(2a^{-3}b^4)^2}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B%283a%5E5b%29%5E%7B2%7D%7D%5Ctimes%20%5Cfrac%7B1%7D%7B%282a%5E%7B-3%7Db%5E4%29%5E2%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{1}{4a^{-6}b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7B1%7D%7B4a%5E%7B-6%7Db%5E8%7D%5D)
![=[\frac{1}{9a^{10}b^2}\times \frac{a^6}{4b^8}]](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1%7D%7B9a%5E%7B10%7Db%5E2%7D%5Ctimes%20%5Cfrac%7Ba%5E6%7D%7B4b%5E8%7D%5D)

Thus, the given expression is equivalent to 
Answer: 714
Step-by-step explanation:
First subtract 813 from 64 with a remainder of 2 then get the remainder and subtract it from 8 which will equal 714