Find the next two terms in the given sequence, then write it in recursive form. A.) {7,12,17,22,27,...} B.) { 3,7,15,31,63,...}
iren [92.7K]
Answer:
A) a_n = 5n + 2
B) a_n = (2^(n + 1)) - 1
Step-by-step explanation:
A) The sequence is given as;
{7,12,17,22,27,...}
The differences are:
5,5,5,5.
This is an arithmetic sequence following the formula;
a_n = a_1 + (n - 1)d
d is 5
Thus;
a_n = a_1 + (n - 1)5
Now, a_1 = 7. Thus;
a_n = 7 + 5n - 5
a_n = 5n + 2
B) The sequence is given as;
{ 3,7,15,31,63,...}
Now, let's write out the differences of this sequence:
Differences are:
4, 8, 16, 32
This shows that it is a geometric sequence with a common ratio of 2.
In the given sequence, a_1 = 3 and a_2 = 7 and a_3 = 15
Thus, a_2 = 2a_1 + 1
Also, a_(2 + 1) = 2a_2 + 1
Combining both equations, we can deduce that: a_(n + 1) = 2a_n + 1
Thus; a_n can be expressed as:
a_n = (2^(n + 1)) - 1
If I'm understanding the question right then 10.5^2
Answer:
30
Step-by-step explanation:
It is an equalateral triangle
Answer:
easy peasy (again)
Step-by-step explanation:
given is that, area of the larger one is 25 times more than the smaller one
so, just put it in the area formula,
let the radius of the larger circle be represented by = R
and of the smaller circle be = r
then, (pi) (R)^2 =25 x (pi) (r)^2
=> dividing the equation by pi on both sides, also taking square root on both sides
=> R = 25 r
that would be the radius of the larger circle is 25 times bigger than the smaller radius
(all u need is to pay attention to the data given in the question and the relation between all that data itself) then it'll look like magic of how the question gets solved...the answer is always in front of you, only thing is to look harder ...good luck with what you are aiming to achieve
Answer:
Option D
Step-by-step explanation:
We are given the two points of (5, 11) and (-5, -1).
Use the slope formula.
The correct option should be Option D.
Hope this helps you.
