I don't know why you need the quadratic formula.
If it takes 0.5 seconds before stepping on the breaks while going 16 m/s, then you travel 8 meters before anything happens. That means you are 44-8 = 36 meters away from the deer now.
v^2 = v_initial^2 + 2(acceleration)(distance)
0 = (16 m/s)^2 + 2(-10m/s^2)(distance)
256 m^2/s^2 / (2(10 m/s^2) = distance = 12.8 meters (13 meters after significant figures are taken into account).
The maximum speed would be:
0 = v_initial^2 + 2(-10m/s^2)(36m)
v_initial^2 = 720m^2/s^2
v_initial = 27 mph
Y = 9/4x + 5....slope here is 9/4. A parallel line will have the same slope.
y = mx + b
slope(m) = 9/4
(25,3)....x = 25 and y = 3
now we sub and find b, the y int
3 = 9/4(25) + b
3 = 225/4 + b
3 - 225/4 = b
12/4 - 225/4 = b
-213/4 = b
so ur equation is : y = 9/4x - 213/4
Answer:
A
Step-by-step explanation:
check the above attachment to verify the answer.
Answer:
0+1+2+3+4+5+6=21
Step-by-step explanation:
Since integers are given as x1, x2, x3, x4, x5, x6, and x7. This means they are consecutive integers divisible by 7.
Thus no matter which 7 consecutive integers are these, their reminders will always be in the order of 0,1,2,3,4,5 & 6.
So their sum will be 0+1+2+3+4+5+6=21.