Answer: B (2,1)
You know what y is (x-1) so you substitute that for y in the other equation.
3x+ ((4)(x-1))=10
3x+4x-4=10
7x=14
x=2
Then put x=2 into y=x-1
y=2-1
y=1
T=an+b
subtract an from each side
b=t-an
<span>2x − 3 < x + 2 </span>
<span>∴ x − 3 < 2 </span>
<span>∴ x < 5 </span>
<span>x + 2 ≤ 3x + 5 </span>
<span>∴ 2 ≤ 2x + 5 </span>
<span>∴ -3 ≤ 2x </span>
<span>∴ -3/2 ≤ x </span>
<span>-3/2 ≤ x < 5</span>
Option 3 or 4 would be your correct answer
