Solving radical equation

Mathematics

1 answer:

Darya [45]4 years ago

6 0

$\bf \sqrt{k-9}-\sqrt{k}=-1\implies \sqrt{k-9}=\sqrt{k}-1\impliedby \textit{squaring both sides}
\\\\\\
(\sqrt{k-9})^2=(\sqrt{k}-1)^2\implies k-9=(\sqrt{k}-1)(\sqrt{k}-1)\impliedby \textit{FOIL}
\\\\\\
k-9=k-2\sqrt{k}+1\implies -10=-2\sqrt{k}\implies \cfrac{-10}{-2}=\sqrt{k}
\\\\\\
\sqrt{\cfrac{-10}{-2}}=k$

You might be interested in

A manufacturer says that the diagonal measurement of a laptop computer is 16 inches. Find the relative error of this measurement

RoseWind [281]

Answer:

As this is incomplete, it lacks the value of actual error.

Here, we do not know the actual value. so let's assume it is 1 inch

Relative Error = 6.25 % ≈ 6.3% = D

Step-by-step explanation:

As this is incomplete, it lacks the value of actual error.

We are asked to calculate the relative of the measurement.

Relative error formula = Actual error/Measurement x 100

Here, we do not know the actual value. so let's assume it is 1 inch

Actual value = 1 inch

Measurement = 16 inch

Relative Error = 1/16 x 100

Relative Error = 6.25 % ≈ 6.3% = D

D. 6.3%

4 0

4 years ago

A moving company drove one of its trucks 100,042 miles one year. A second truck was

hram777 [196]

319049

as 100,042 + 98,117 + 120,890 = 319,049

7 0

3 years ago

Who can solve this question?I will mark them as branlist.

mina [271]

Answer:

See below

Step-by-step explanation:

$\overrightarrow a= \bigg(\frac{5}{\sqrt 34},\:\frac{3}{\sqrt 34}\bigg)$

We have to show that $\overrightarrow a$ is an unit vector.

To show this, we will find the modulus of $\overrightarrow a$ and if its value is 1, it will be a unit vector.

So,

$| \overrightarrow a| = \sqrt{\bigg(\frac{5}{\sqrt 34} \bigg) ^{2}+\bigg(\frac{3}{\sqrt 34}\bigg)^{2} } \\ \\ | \overrightarrow a| = \sqrt{\frac{25}{ 34} +\frac{9}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{\frac{25 + 9}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{\frac{34}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{1} \\ \\ | \overrightarrow a| = 1$