Question

Who can solve this question?I will mark them as branlist.​

Answer 1

Answer:

See below

Step-by-step explanation:

$\overrightarrow a= \bigg(\frac{5}{\sqrt 34},\:\frac{3}{\sqrt 34}\bigg)$

We have to show that $\overrightarrow a$ is an unit vector.

To show this, we will find the modulus of $\overrightarrow a$ and if its value is 1, it will be a unit vector.

So,

$| \overrightarrow a| = \sqrt{\bigg(\frac{5}{\sqrt 34} \bigg) ^{2}+\bigg(\frac{3}{\sqrt 34}\bigg)^{2} } \\ \\ | \overrightarrow a| = \sqrt{\frac{25}{ 34} +\frac{9}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{\frac{25 + 9}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{\frac{34}{ 34} } \\ \\ | \overrightarrow a| = \sqrt{1} \\ \\ | \overrightarrow a| = 1$

Thus, $\overrightarrow a$ is a unit vector.