Answers in bold
- x+3
- x+3
- x-3
- -x-120
- -x+120
- x+12
- -x-12
- 0
- x/3
- -x/3
Ignore the non bold numbers up front as they are just meant to keep track of which answer goes where. The result to problem 8 is zero, while everything else involves x somehow.
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Explanation:
Use a graphing tool like Desmos to see that y = |x+3| is a V shaped graph. The vertex is at (-3,0). Stuff to the right of the vertex is x > -3. The interval x > 5 is a subset of the previous inequality.
In other words, if you pick something larger than 5, then its automatically larger than -3.
The y = |x+3| is composed of the linear equations y = x+3 and y = -(x+3) depending if you are on the right branch or the left branch respectively.
We go for y = x+3 since we're on the right hand side.
Use this type of trick to answer the others in this fashion.
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For problem 8, we replace x with -12 and compute like so
|x-(-12)| = |x+12| = |-12+12| = |0| = 0
Answer:
7/4
Step-by-step explanation:
1/2 x 2 = 1
3/4 + 1 = 7/4 or 1 3/4
Answer:
22cm
See explanation below
Step by step explanation:
The question is incomplete without the diagram of the shape or its dimensions.
From the question, we are to determine the perimeter of the circle.
Let's consider the following question by determining the perimeter of a circle. If diameter is 7cm. Use pi as 3.14.
Perimeter of circle = circumference of circle
circumference of circle = 2πr
Radius = diameter/2 = (7/2)cm
circumference of circle = 2πr
= 2×π×(7/2) = (14/2)×3.14
= 7×3.14
=21.98cm
circumference of circle = 22cm (nearest tenth)
Perimeter of circle = 22cm
Answer:
it would be a
Step-by-step explanation:
