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baherus [9]
2 years ago
7

Pretty Easy questions. Answer for lots of points.

Mathematics
2 answers:
Olegator [25]2 years ago
7 0

Answer:

1) x+3

2) x+3

3) x-3

4) -x-120

5) -x+120

6) x+12

7) -x-12

8) 0

9) x/3

10) -x/3

Step-by-step explanation:

Agata [3.3K]2 years ago
6 0

Answers in bold

  1. x+3
  2. x+3
  3. x-3
  4. -x-120
  5. -x+120
  6. x+12
  7. -x-12
  8. 0
  9. x/3
  10. -x/3

Ignore the non bold numbers up front as they are just meant to keep track of which answer goes where. The result to problem 8 is zero, while everything else involves x somehow.

===============================================

Explanation:

Use a graphing tool like Desmos to see that y = |x+3| is a V shaped graph. The vertex is at (-3,0). Stuff to the right of the vertex is x > -3. The interval x > 5 is a subset of the previous inequality.

In other words, if you pick something larger than 5, then its automatically larger than -3.

The y = |x+3| is composed of the linear equations y = x+3 and y = -(x+3) depending if you are on the right branch or the left branch respectively.

We go for y = x+3 since we're on the right hand side.

Use this type of trick to answer the others in this fashion.

----------

For problem 8, we replace x with -12 and compute like so

|x-(-12)| = |x+12| = |-12+12| = |0| = 0

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hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

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Step-by-step explanation:

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so we only expect one solution.

You said that <span><u>3x+9 = 21+7x </u>

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