Evaluate 3^-33^43*3^-5

1 answer:

8 0

To multiply exponents with like bases, simply add the exponents...

3^-3 × 3^4 × 3 × 3^-5 =

add exponents across, remember just 3 means 3^1.

-3 + 4 + 1 + -5 = -3

answer is 3^-3

You might be interested in

Samuel walks in the Labor Day parade. He walks 3 1/4 miles along the parade route and 2 5/6 miles home. How many miles does Samu

Afina-wow [57]

Find a common denominator which is 12

1*3=3 4*3=12 so 3 3/12

then 5*2=10 6*2=12 so 2 10/12

2 10/12+3 3/12= 5 13/12

13/12= 1 1/12 plus 5= 6 1/12

so your answer would be 6 1/12

3 0

3 years ago

Read 2 more answers

Please<br>Help me I don't get this!

Vikentia [17]

The 4 in and the 6 in are the same but the difference between the two triangles are 1.5

6:4 = 1.5
So if 12 = 1.5 (?)
The (?) = 8

4 0

2 years ago

What is the slope of the line that contains the points (-1,9) and (5,21)

geniusboy [140]

Y-y
——-
X-x

21-9=12
5-(-1) =6
So the answer is D

7 0

3 years ago

What is twice the difference of sixteen minus 13

Viefleur [7K]

Answer:

Step-by-step explanation:

$2(16-13)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(16-13\right)\::\quad 3\\\\=2\times\:3\\\\= 6$

3 0

3 years ago

Find y' by implicit differentiation √x +√y =1

AleksandrR [38]

Differentiate both sides with respect to x

$\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}$

5 0

3 years ago

Evaluate 3^-3*3^4*3*3^-5

Evaluate 3^-33^43*3^-5