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3 years ago

Solve this system by elimination 10x+6y=14 -x-6y=-23

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

8 0

Answer:

(-1, 4)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define systems

10x + 6y = 14

-x - 6y = -23

Step 2: Solve for x

Elimination

Add 2 equations together: 9x = -9
Divide 9 on both sides: x = -1

Step 3: Solve for y

Define original equation: -x - 6y = -23
Substitute in x: -(-1) - 6y = -23
Multiply: 1 - 6y = -23
Subtract 1 on both sides: -6y = -24
Divide -6 on both sides: y = 4

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3 years ago

Read 2 more answers

tank a has 100 gallons of water and is being filled at a rate of 2 gallons per hour. tank b has 140 gallons and is being drained

Artist 52 [7]

Answer:

5 hours must pass

Step-by-step explanation:

Graph the equations y = 2x + 100 and y = -6x + 140

Then find the x intercept of their intersection, in this case, that is 5

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3 years ago

During a promotional weekend a state fair gives a free admission to every 175th Person who enters the fair on Saturday there wer

emmasim [6.3K]

Answer:

Step-by-step explanation:

If every 175th person gets free admission, that means

175th

175 * 2 = 350th

175 * 3 = 525th

person gets free admission and so on...

This basically means "how many 175s are there is 6742 (for first day) and 5487 (for 2nd day)?"

We would need to divide and see the WHOLE number, not the fractional(decimal) amount remaining. So

1st Day:

6742/175 = 38.53

This means 38 people will get free admission

2nd Day:

5487/175 = 31.35

This means 31 people will get free admission

In the 2 days, total of 38 + 31 = 69 people will get free admission

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3 years ago

Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted

Misha Larkins [42]

Answer:

$\frac{15}{28}$ is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red $= 3 + 5 = 8$

Probability of getting blue $= \frac{3}{8}$

Probability of not getting a blue $=\frac{5}{8}$

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

First Draw Blue, Second Draw Not Blue:

1st Draw: $P(Blue) = \frac{3}{8}$

2nd Draw: $P(Not\:Blue)=\frac{5}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}$

First Draw Not Blue, Second Draw Not Blue:

1st Draw: $P(Not\:Blue)=\frac{5}{8}$

2nd Draw: $P(Not\:Blue)=\frac{3}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}$

To get the probability of exactly one blue, we add both of the events:

$\frac{15}{56}+\frac{15}{56}=\frac{15}{28}$

4 0

3 years ago