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PSYCHO15rus [73]
3 years ago
9

You complete your database, and the company begins using it. Shortly afterwards, two GearUp buyers, Cora and Owen, work together

on a sale from a supplier called TennisSource. Both come to you complaining that their entry into the "Supplier History" part of the database is not showing up. Instead, the field reads "invalid entry." What is most likely the problem?
Computers and Technology
1 answer:
Olegator [25]3 years ago
3 0

Answer: Multi-user issue

Explanation: A database management system scheme can have multi-user issue when the designing of the system is not made properly. The multi user issue rises when the users concurrently access the data from the database and related error get invoked due to some reason like  repeatable reading issue, serialization, etc.

The reading problem is usually can be related to reading of the database in  uncommitted manner, uncommitted reading, repeatedly reading etc.Thus, Cora and Owen are accessing the database concurrently which can create multi-user issue.

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Sorting is the process of arranging the data on the basis of some property or attribute. Using the find command, conducting a query, and mapping the data would not help.

There are various sorting algorithms like the bubble sort, selection sort, insertion sort, quick sort, and merge sort. Out of all the attributes, one or a combination of attributes can be selected to serve as the basis for sorting.

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This question involves the implementation of the PasswordGenerator class, which generates strings containing initial passwords f
liq [111]

The following code will be used for the PasswordGenerator class.

<u>Explanation:</u>

import java.util.Random;

public class PasswordGenerator {

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   private String prefix;

   private int length;

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       this.prefix = prefix;

       this.length = length;

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       this.prefix = "A";

       this.length = length;

   }

   public String pwGen(){

       String pwd= this.prefix+".";

       for(int i=1;i<=this.length;i++){

           pwd+=random.nextInt(10);

       }

       passwordsGenerated+=1;

       return pwd;

   }

   public int pwCount(){

       return passwordsGenerated;

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   public static void main(String[] args) {

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       System.out.println(pw1.pwCount());

       System.out.println(pw1.pwGen());

       System.out.println(pw1.pwGen());

       System.out.println(pw1.pwCount());

       PasswordGenerator pw2 = new PasswordGenerator(6);

       System.out.println(pw2.pwCount());

       System.out.println(pw2.pwGen());

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8 0
3 years ago
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Answer:

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