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KengaRu [80]
3 years ago
13

One step inequalities

Mathematics
1 answer:
pishuonlain [190]3 years ago
3 0
Whats the question ? 
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Write an equation of a line parallel to y = -2x + 3 that passes through (-2,-1)
ElenaW [278]

\boxed{y=-2x-5}

<h2>Explanation:</h2>

The slope-intercept form of the equation of a line:

y=mx+b \\ \\ \\ Where: \\ \\ m:Slope \\ \\ b:y-intercept

The given line has the following characteristics:

y=-2x+3 \\ \\ \\ So: \\ \\ m=-3 \\ \\ b=3

So the line we are looking for needs to be:

y=-2x+b \\ \\ \\ It \ passes \ through \ (-2,-1): \\ \\ -1=-2(-2)+b \\ \\ b=-1-4 \\ \\ b=-5

So, the equation of the line would be:

\boxed{y=-2x+3}

<h2>Learn more:</h2>

Many-to-one function: brainly.com/question/12881881

#LearnWithBrainly

3 0
4 years ago
Are the ratios 25/45 and 15/27 proportional. explain
Nataly_w [17]
If a/b and c/d are proportional then (a/b)(d/c)=1, aka ad=bc


25/45=15/27?
25*27=45*15?
675=675?
true

they are proportional
6 0
4 years ago
Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x5y2 − x4y
il63 [147K]

Answer:

dx/dy =  (x^4 -  2x^5y -  6xy^2) /  (5x^4y^2 - 4x^3y +  2y^3).

Step-by-step explanation:

x^5y^2 − x^4y + 2xy^3 = 0

Applying the Product and Chain Rules:

y^2*5x^4*dx/dy + 2y*x^5 - (y*4x^3*dx/dy + x^4) + (y^3* 2*dx/dy + 3y^2*2x) =0

Separating the terms with derivatives:

y^2*5x^4*dx/dy - y*4x^3*dx/dy + y^3* 2*dx/dy =  x^4 -  2y*x^5 -  3y^2*2x

dx/dy =  (x^4 -  2x^5y -  6xy^2) /  (5x^4y^2 - 4x^3y +  2y^3)

7 0
3 years ago
Read 2 more answers
What are the roots of the function shown below?
katrin [286]

Answer:

x = 1 and x = -3

Step-by-step explanation:

roots are points that y = 0

in two points we have this

x = 1 and x = -3

6 0
3 years ago
5m – 8 = 3m + 8 for m
statuscvo [17]

Answer:

m=8

Step-by-step explanation:

6 0
3 years ago
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