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3 years ago

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Which of the following describes the correct process for solving the equation 3x+6=21

1 answer:

DochEvi [55]3 years ago

4 0

Answer: Subtract 6 from both sides. Then, one would get 3x=15. Divde by 3 on both sides. x=5.

Step-by-step explanation:

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-9b-6=-3b +48<br> Step by step

Travka [436]

Answer:

b = -9

Step-by-step explanation:

1. Move the variables to the left side. Be sure to change the terms (add/subtract)

-9b-6 = -3b+48

-9b+3b-6 = 48

2. Combine like terms.

-9b+3b-6 = 48

-6b = 48 + 6

3. Divide both sides by -6.

-6b = 54

b = -9

7 0

3 years ago

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Which scatterplot shows the strongest negative linear correlation

Andreyy89

Answer:it’s c

Step-by-step explanation:

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3 years ago

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how do you get the answer to y=2x-3? It has to with line graphs and I am completely lost! If anyone can take me through it step

Lerok [7]

You know that -3 is the Y intercept(vertical graph line) and then continue 2/1 every x value that is plugged in.

3 0

3 years ago

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A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses

mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for $x$ days.

So, for $x$ days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = $\frac{360}{x}$

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = $(x+4)$ days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= $(\frac{360}{x}-3)$

Total expense in dollars can now be given as: $(x+4)(\frac{360}{x}-3)$

Simplifying by using distribution (FOIL).

$(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))$

$360-3x+\frac{1440}{x}-12$

$348-3x+\frac{1440}{x}$

We know total expense remains the same which is = $360.

So, we have the equation as:

$348-3x+\frac{1440}{x}=360$

Multiplying each term with $x$ to remove fractions.

$348x-3x^2+1440=360x$

Subtracting $348x$ both sides

$348x-348x-3x^2+1440=360x-348x$

$-3x^2+1440=12x$

Dividing each term with -3.

$\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}$

$x^2-480=-4x$

Adding $4x$ both sides.

$x^2+4x-480=-4x+4x$

$x^2+4x-480=0$

Solving using quadratic formula.

For a quadratic equation: $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plugging in values from the equation we got.

$x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16+1920}}{2}$

$x=\frac{-4\pm\sqrt{1936}}{2}$

$x=\frac{-4\pm44}{2}$

So, we have

$x=\frac{-4+44}{2}$ and $x=\frac{-4-44}{2}$

$x=\frac{40}{2}$ and $x=\frac{-48}{2}$

∴ $x=20$ and $x=-24$

Since number of days cannot be negative, so we take $x=20$ as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0

3 years ago

Simplify: 4(3x^2y^4)^3 / 2x^3y^5)^4

Semenov [28]

Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> (((3•(x2))•(y4))3) 4•—————————————————— ((2x3•(y5))4) </span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> ((3x2 • (y4))3) 4 • ——————————————— 24x12y20 </span><span> Step 3 :</span><span> 33x6y12 Simplify ———————— 24x12y20 </span></span>Dividing exponential expressions :

<span> 3.1 </span> <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>

Dividing exponential expressions :

<span> 3.2 </span> <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>

<span>Equation at the end of step 3 :</span><span> 27 4 • —————— 16x6y8 </span><span>Step 4 :</span>Final result :<span> 27 ————— 4x6y<span>8</span></span>

6 0

3 years ago

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