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Tamiku [17]
2 years ago
12

Is -2.7,-9,-30,-100 a geometric sequence ?

Mathematics
1 answer:
Fiesta28 [93]2 years ago
3 0
Hello : 
-100/-30 = 10/3
-30/-9 = 10/3
-9/-2.7 = 10/3
<span>geometric sequence the common ratio is : 10/3</span>
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I don’t know how to solve for Q.
Naya [18.7K]

Answer:

  ∠Q = 75°

Step-by-step explanation:

Start by recognizing that the triangle is isosceles (the long sides are marked as being equal-length). That means angles Q and R have the same measure.

Next, you use the fact that the sum of angles is 180° to write an equation.

  ∠R +∠P +∠Q = 180°

  (2x +15)° +x° +(2x +15)° = 180° . . . . substitute the known values

  5x +30 = 180 . . . . . . . . . . . . . . . . divide by °, collect terms

  5x = 150 . . . . . . . . subtract 30

  x = 30 . . . . . . . divide by 5

Then angle Q is ...

  ∠Q = (2x +15)° = (2×30 +15)°

  ∠Q = 75°

8 0
2 years ago
Express 0.0426 in standard form<br><br>​
dem82 [27]

Answer:

4.26 × 10-2

Step-by-step explanation:

6 0
2 years ago
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Which of the following equations has the solution x= all real numbers?
Marysya12 [62]
The answer is C
4(3-x)+6x=3x+12-x  All real numbers are solutions.
5 0
3 years ago
Compute a value for t that satisfies the equation below. "-2/3" t - 2 = - 3
Dima020 [189]

Answer:

t = 3/2

Step-by-step explanation:

Instead of randomly guessing values of "t" that will satisfy the equation, you can easily find the correct value by solving the equation in terms of "t". In other words, you can set the equation equal to "t" to find the final answer.

(-2/3)t - 2 = -3                             <----- Original equation

(-2/3)t = -1                                   <----- Add 2 to both sides

t = 3/2                                        <----- Divide both sides by -2/3

You can check this value by plugging it into "t" and determining whether both sides of the equations will be equal.

(-2/3)t - 2 = -3                            <----- Original equation

(-2/3)(3/2) - 2 = -3                      <----- Plug 3/2 into "t"

-6/6 - 2 = -3                               <----- Multiply -2/3 and 3/2

-1 - 2 = -3                                    <----- Simplify -6/6

-3 = -3                                        <----- Subtract

6 0
1 year ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
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