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Novay_Z [31]
3 years ago
8

The temperature in Minneapolis at 9

Mathematics
2 answers:
melisa1 [442]3 years ago
8 0

Easy! Your answer would be 0°

Valentin [98]3 years ago
3 0

The Temperature at noon was 0° Because -8 + 8 = 0

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The high school took two field trips to the Newport Aquarium many many years ago. They used school buses and vans to transport a
il63 [147K]

Answer:

bus = 43

van 12

Step-by-step explanation:

This can be solved using simultaneous equations

Let v represent the number of students that a van carries

Let b represent the number of students that a bus carries

the following equations can be derived from the question

3v + 2b = 122 eqn 1

5v + 3b = 189  eqn 2

Multiply eqn 1 by 5 and eqn 2 by 3

15v + 10b = 610  eqn 3

15v + 9b = 567 eqn 4

Subtract equation 4 from 3

b = 43

Substitute for b in equation 1

3v + 2(43) = 122

solve for v

v = 12

5 0
3 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
Math question screen shot down below
Oksanka [162]

Answer:

The correct answer is A, Point P

Step-by-step explanation:

since the additive inverse of 2 is -2 because -2 + 2 = 0 the correct choice must be choice A, Point P.

8 0
3 years ago
Read 2 more answers
6437585839765349 + 52367538546941478 ?
Harrizon [31]

5.880512439 x 10^16

5.880512439 x 10^16Hope this helps!

4 0
2 years ago
5/6 of the students completed homework last night, but only 3/4 of those students did their work correctly. How many students di
Kisachek [45]

Answer:


Step-by-step explanation:

first your going to do the least common multiple which is 12 for both then your going to subtract because were trying to find out how many students did there work correctly. so, whatever you do to the denominator you do to the numerator so, its going to be 10/12 - 9/12= 1/12 is your answer.

8 0
3 years ago
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