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Anestetic [448]
3 years ago
14

56 with 75% increase

Mathematics
1 answer:
valina [46]3 years ago
7 0

Answer:133

Step-by-step explanation:

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Change 3Y - 2X = -6 to the slope-intercept form of the equation of a line.
k0ka [10]

Answer:

y = 2/3x -2

Step-by-step explanation:

The slope intercept form of a line is

y = mx+b where m is the slope and b is the y intercept

3y -2x = -6

Solve for y

Add 2x to each side

3y = 2x-6

Divide by 3

3y/3 = 2x/3 -6/3

y = 2/3x -2

3 0
4 years ago
PLEASE HELP :) I will give all points
yan [13]

answer choice a

x^2 - 5x - 1 = 0

a=1, b=-5, and c=-1

next you plug in the numbers into the quadratic formula

-(-5) plus or minus the square root of (-5)^2 - 4(1)(-1)/ 2(1)

after you simply, you should get 5 plus or minus the square root of 29, which is answer choice a

8 0
3 years ago
The price of a digital camera sold in stores is $129. It is sold on eBay for $65. What is the percent decrease from the store's
SpyIntel [72]
Percent decrease=100*decrease/original

decrease=original-saleprice
decrease=129-65
decrease=64

percent decrease=100*64/129
percent decrease=100*0.496124
percent decrase=49.6124
about 50% decrase
8 0
3 years ago
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melisa1 [442]
What are the choices?
5 0
3 years ago
The time it takes you to go a certain distance varies inversely with the speed of travel. Suppose it takes you 4 hours to get to
fgiga [73]
\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{time it takes varies inversely with the speed rate}\qquad \stackrel{time}{t}=\cfrac{k}{\stackrel{rate}{r}}
\\\\\\
\textit{we also know that }
\begin{cases}
t=\stackrel{hrs}{4}\\
r=\stackrel{mph}{50}
\end{cases}\implies 4=\cfrac{k}{50}\implies 200=k
\\\\\\
\boxed{t=\cfrac{200}{r}}
\\\\\\
\textit{if your rate r = 40, what is your distance \underline{t}?}\qquad t=\cfrac{200}{40}
3 0
3 years ago
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