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katrin [286]
3 years ago
11

The distance around a figure is called _____​

Mathematics
2 answers:
Stells [14]3 years ago
5 0

The distance around a figure is the perimeter, although around a circle is the perimeter is actually called the circumference.

algol [13]3 years ago
3 0

Answer:

<h2>Perimeter</h2>

Step-by-step explanation:

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I need help with this.
ser-zykov [4K]

Answer:

(3z+15) cm

Step-by-step explanation:

Perimeter: z cm + 8 cm + (z+3) cm + (z+4) cm = z cm + (z+3) cm + (z+4) cm +8 cm = (3z + 7) cm + 8 cm = (3z+15) cm.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=599.966%20to%204%20significant%20fugurs" id="TexFormula1" title="599.966 to 4 significant fugu
Katarina [22]

Step-by-step explanation:

Significant figures mean all none zero digits so 599.966 to 4 significant figures would be = 600.

7 0
3 years ago
Does anyone know the equation??
il63 [147K]

Answer:

y= -1/3x - 4

Step-by-step explanation:

there you go

7 0
3 years ago
HELP PLS I HAVE 2 MINUTES IF NOT SHES GONNA CALL MY MOM
alukav5142 [94]

Answer:

a) p = -84

b) m = 23

Step-by-step explanation:

p = -4

a = 19 + 2p  

⇒ 19 + 2 x -4

⇒ -84

m = 3

m^{3} - 4

⇒ 3^{3} - 4

⇒ 23

4 0
3 years ago
Find measure of angle E
ki77a [65]

The measure of ∠E will be equal to 38°.

Given,

m∠BFE = 118° and m∠C = 86°

And BF bisects ∠ABD

From the Property of Linear Pair,

∠AFB + ∠BFE = 180°

=> ∠AFB + 118° = 180°

=> ∠AFB = 62°

Now, we can see that ∠AFB and ∠FBD are equal because they are alternate angles.

And ∠FBD and ∠ABF are equal because BF bisects ∠ABD.

So, In ∆ABF,

∠AFB + ∠ABF + ∠BAF = 180° (because of the angle sum property of a triangle)

=>62° + 62° + ∠BAF = 180°

=>∠BAF = 180° - 124°

=> ∠BAF = 56°

Similarly, in ∆ABE,

∠A +∠C  +∠E = 180°

=> 56° + 86° + ∠E = 180°

=> ∠E = 38°

Therefore, m∠E = 38°.

Learn more about Angles of Triangle at

brainly.com/question/28736528

8 0
2 years ago
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