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Leto [7]
3 years ago
10

A motorboat travels 385 kilometers in 7 hours going upstream and 455 kilometers in 5 hours going downstream. What is the rate of

the boat in still water and what is the rate of the current?
Mathematics
1 answer:
dangina [55]3 years ago
4 0

Answer:

Rate of the boat in still water 73 mi/hr

Rate of the current 18 mi/hr

Step-by-step explanation:

Calculation to determine the rate of the boat in still water and the rate of the current

Let B represent the speed of the boat in still water.

Let S represent the speed of the stream

Speed upstream = B-S.

Speed downstream = B+S.

Using the equation for distance

Distance=Rate * Time

Upstream

(B-S)7 = 385

(B+S)5= 455

Simplify first:

B-S=385/7

B-S = 55

B+S=455/5

B+S = 91

Solve by elimination. Add the two equations.

2B=55+91

2B = 146

B=146/2

B = 73 mi/hr

Substitute this into either equation and solve for S.

B+S = 91

73+S = 91

S=91-73

S = 18 mi/hr

Therefore the rate of the boat in still water is 73 mi/hr and the rate of the current is 18 mi/hr

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Andrew is riding his bike. He biked a distance of 14 miles at a rate of 7 miles per hour. Using the distance formula, d = rt, so
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<h3>How to illustrate the information?</h3>

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Step-by-step explanation:

Statement 1.

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Reason 1.  

Given

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(i) given  

(ii) given and  

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Help please! I have choral practice...
Maslowich
<span>This polygon is composed of a right triangle and <span>a parallelogram.

The area of right angle :
A_\Delta=\frac{1}{2}\cdot15\cdot8=\frac{1}{2}\cdot120=\boxed{60\ (cm^2)}

The area of the </span></span><span>parallelogram</span>:
A_P=15\cdot(13-8)=15\cdot5=\boxed{75\ (cm^2)}

The area of the polygon is equal:A=A_\Delta+A_P

Therefore, the answer is:
\boxed{\boxed{A=60\ cm^2+75\ cm^2=135\ cm^2}}
7 0
3 years ago
Read 2 more answers
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