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Novosadov [1.4K]
3 years ago
15

May someone help me on this question please

Mathematics
1 answer:
Oduvanchick [21]3 years ago
4 0
For the past 52 weeks, the high and low for the past 52 weeks would be the high and the low under the column for the 52 weeks.

52 week High = $71.36

52 week Low =  $42.86
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(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
3 years ago
1/5+1/4+2/5 this is adding fractions with unlike denominators what is the answer
attashe74 [19]
What you would do is change all the fractions to 20ths so they have a common denominator. For 1/5, you multiply 4x5 to get 20 in the denominator. Whatever you multiply on the bottom, you must do at the top. Do that for all fractions and you would get this:
4/20 + 5/20 + 8/20= 17/20 because denominator stays the same, add the values in the numerator.
ANSWER: 17/20
5 0
3 years ago
What kind of graph is characterized by presenting data values as portions of a circle?
Levart [38]
<span>B. pie chart graph is characterized by presenting data values as portions of a circle </span>
7 0
4 years ago
Read 2 more answers
Solve both questions please ❤️❤️
harina [27]

Answer:

1. y=7.2

2. x=18

Step-by-step explanation:

1. Triangles CMN and CBA are similar triangles (by AAA postulate). Similar triangles have proportional corresponding sides, so

\dfrac{CM}{CB}=\dfrac{CN}{CA}\\ \\\dfrac{12}{12+y}=\dfrac{10}{10+6}\\ \\12\cdot 16=10\cdot (12+y)\\ \\192=120+10y\\ \\10y=72\\ \\y=7.2

2. GK is angle G bisector. Use angle bisector's property:

\dfrac{GH}{GI}=\dfrac{KH}{KI}\\ \\\dfrac{40}{24}=\dfrac{30}{x}\\ \\40x=24\cdot 30\\ \\4x=24\cdot 3\\ \\x=6\cdot 3=18

8 0
3 years ago
Anyone know the answer?
Svetradugi [14.3K]
I think it may be A.
8 0
3 years ago
Read 2 more answers
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