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VLD [36.1K]
3 years ago
12

81/11 as a mixed number

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Answer:

7  4/11

Step-by-step explanation:

81/11= 7  4/11

Sindrei [870]3 years ago
7 0

Answer:

7 4/11

Step-by-step explanation:

this is the answer

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Well Karl rode 5*7=35 miles. So Kelly rode 8*7=56 miles.
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3 years ago
Solve for p. G=8/5(p-4)
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Answer:

\large\boxed{p=\dfrac{5G+32}{8}}

Step-by-step explanation:

\dfrac{8}{5}(p-4)=G\qquad\text{multiply both sides by 5}\\\\8(p-4)=5G\qquad\text{use distributive property}\\\\8p-32=5G\qquad\text{add 32 to both sides}\\\\8p=5G+32\qquad\text{divide both sides by 8}\\\\p=\dfrac{5G+32}{8}

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what is a linear function in the form y=mx+b for the line passing through (4.5, -4.25) with y-intercept 2.5?
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8 0
4 years ago
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Solve the equation 18 + k = 20
Lorico [155]

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3 years ago
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A model for the density δ of the earth’s atmosphere near its surface isδ=619.09−0.000097pwhere p (the distance from the center o
natta225 [31]

Answer: 3.751*10^18kg

Step-by-step explanation:

δ =619.09−0.000097p....equa1 where p (the distance from the center of the earth) is measured in meters and δ is measured in kilograms per cubic meter.

Calculating the density of air at 5km above earth surface

P = 5000m + 6370000m = 6.375*10^6m

δ = 619.09 -(.000097* 6.375*10^6)

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To calculate volume of air around the spherical earth at height 5km

V = (4/3 pai R^3) - (4/3pai r^3) ...equation 3 where R =6.375*10^6m, r = 6.37*10^6

Substituting R and r in equation 2 to solve for volume of air

V = 1.085*10^21 - 1.08*10^21

V = 5.25*10^18m^3

Substituting δ and V into equation 2 to solve for mass of air

M = 0.715 * (5.25*10^18)

M = 3.751*10^18kg

8 0
3 years ago
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