Mulitpilicty is how many times a root repeats
factor
factor x first
x(2x^2+x-1)
using math
(x)(x+1)(2x-1)
no roots repeat
if it is equal to 0 then the roots are
0 multiplicty 1
-1 multiplicty 1
1/2 multiplicty 1
10y^2 - 23y + 12 = 10y^2 - 15y - 8y + 12 = 5y(2y - 3) - 4(2y - 3) = (5y - 4)(2y - 3)
Answer:
the exponent of x is 4
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)/(a^c) = a^(b-c)
a^-b = 1/a^b
__
Answer:
-16=-16
Step-by-step explanation:
You would first do (-4-2) which would be (-6), after you would multiply (-6) by 4 which comes out to be -24, after you would add 3 which would look like this -24+3 but since its a negative it would come out to be -21 then you would do the same thing with 5, it would look like this -21 + 5 but since its negative it would be -16. I hope this helped :)
The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.
<h3>
Could the graphed function have a degree 4?</h3>
For a polynomial of degree N, we have (N - 1) changes of curvature.
This means that a quadratic function (degree 2) has only one change (like in the graph).
Then for a cubic function (degree 3) there are two, and so on.
So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).
Then we can write:
y = a*x^4 + c*x^2 + d
That is a polynomial of degree 4, but if we choose x^2 = u
y = a*u^2 + c*u + d
So it is equivalent to a quadratic polynomial.
Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).
If you want to learn more about polynomials:
brainly.com/question/4142886
#SPJ1
