Answer:
D
Explanation:
Two genes are involved in this case: one coding for eye color and the other for skin color.
According to the question, the allele for Black eyes (B) is dominant over the allele for orange eyes (b) while on the other gene, the allele for green skin (G) is dominant over the allele for white skin (g).
This means both alleles for orange eyes (b) and white skin (g) are recessive i.e masked by their counterpart allele
Since they are recessive, they will only be phenotypically expressed if they are in their homozygous state. i.e same type of allele.
In this case, the parent has orange eyes and white skin i.e.both recessive traits
Therefore, the genotype will be bbgg.
Answer:
c. They produce functional β-galactosidase that cleaves X-gal.
Explanation:
β-galactosidase is an enzyme capable of catalyzing the enzymatic hydrolysis of β-galactosides into monosaccharides by hydrolyzing the β-glycosidic bond. On the other hand, X-gal is an analog of lactose composed of galactose, which is widely used in laboratories for the detection of β-galactosidase. In the presence of β-galactosidase, X-gal is hydrolyzed by cleaving its β-glycosidic bond, thereby confirming the presence of β-galactosidase.
Answer:
The gene for having a tall stature is a recessive trait. So the man can have only as genotype "aa". The short woman can have instead as genotype either Aa or AA. in the first case, we have both tall and short children while in the second case only short children.
So the answer is A) All the progeny may be tall.
