All categories

3 years ago

If m∠A =91° and m∠B = 40°, find m∠1. A) 89° B) 122° C) 131° D) 140°

Mathematics

1 answer:

Yanka [14]3 years ago

6 0

Answer: is that a high school math it looks hard to me

Step-by-step explanation??

You might be interested in

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

1 year ago

john has earnes a 77, 76 and a 84 on his first three projects of the semester.if he hopes to have a b average (80 or above) what

lukranit [14]

He need to have at least an 83

8 0

3 years ago

Problem 1

Salsk061 [2.6K]

Answer:

a- 3 batches

$1 \frac{1}{2} = 1.5$

c- 0.5 batches

3 0

3 years ago

What is the area of a square rug that measures 6 feet on a side? 3 square feet 24 square feet 12 square feet 36 square feet

QveST [7]

Well we know the area of a square is l*w, or s^2. So we can use s^2 where s=6 in your case. Now 6^2 is 6*6, which is 36.

So the area of a square rug that measures 6 feet is 36 feet

Answer= 36 feet

4 0

3 years ago

Read 2 more answers

All the given quadrilaterals in the picture on the right are squares and #1 ≅ #3, #2 ≅ # 4. find the area of the shaded region,

Anika [276]

Answer:

Step-by-step explanation:

If you have a square of side $l$ , its diagonal would be $l\sqrt{2}$ , and its area $l^2$

If the big square has a area of 900, this implies that its side is $\sqrt{900}$ , so the two diagonal of squares 2 and 4 added together would be $\sqrt{900}$ , therefore one diagonal wold be $\frac{\sqrt{900}}{2}$ . and its side $\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}}$ . The area (of one square) is $(\frac{\sqrt{900}}{2}\frac{1}{\sqrt{2}})^2=\frac{225}{2}$

finally the two areas combined (squares 2 and 4) would be 225

6 0

3 years ago