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3 years ago

Which subjects does the Aspire test assess?

Business

1 answer:

Nikolay [14]3 years ago

7 0

Answer:

five subject areas: English, mathematics, reading, science, and writing

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On January 1, a machine with a useful life of 5 years and a salvage value of $15000 was purchased for $115000. What is the depre

grandymaker [24]

Answer:

Annual depreciation (year 2)= $20,000

Explanation:

Giving the following information:

Purchase price= $115,000

Salvage value= $15,000

Useful life= 5 years

To calculate the annual depreciation under the straight-line method, we need to use the following formula:

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= (115,000 - 15,000) / 5

Annual depreciation= $20,000

5 0

2 years ago

Unexpected weather can even have an effect on the business cycle. true or false

gulaghasi [49]

True.................

7 0

2 years ago

Read 2 more answers

Jessica's grandfather lives alone and still works. he told jessica that he is concerned about what might happen if he could no l

SOVA2 [1]

Jessica's grandfather is concerned about his physical well-being. He thinks about his health and physical health and has fears that maybe in the future he will not have the strength. The physical health is connected to mental and emotional health.

8 0

2 years ago

A series of monthly cash flows is deposited into an account that earns 12% nominal interest compounded monthly. Each monthly dep

nirvana33 [79]

Answer:

The amount left in the account after last withdrawal is $61,945

Explanation:

The first monthly deposit occurred on June 1, 2008 and the last monthly deposit will be on January 1, 2015 = 80 deposit

Monthly deposit = 2,100

Interest rate = 12% / 1% per month

Firstly, we calculate the future worth of the monthly deposit

FW = A(F/A, i, n)

A = 2,100, i = 1%, n= 80

FW = $2100*[(1+0.01)^80 - 1 / 0.01]

FW = $2100*[2.216715 - 1 / 0.01]

FW = $2100*(121.671)

FW = $255,509.10

We calculate the effective interest rate

i(effective) = (1 + i nominal monthly interest rate)^n - 1

i `%, n = 3(no of months in quarter)

i (effective) = (1+0.01)^3 - 1

i (effective) = (1.01)^3 - 1

i (effective) = 1.030301 - 1

i (effective) = 0.030301

i (effective) = 3.0301%

The effective quarterly interest rate is 3.0301%

We calculate the future worth of the quarterly drawings

FW = A[(1+i)^n - 1 / i]

A = 5,000(drawing), i = 3.0301%, n = 26(number of drawings)

FW = 5,000*[(1+0.030301)^26 - 1 / 0.030301]

FW = 5,000*[2.17303717 - 1 / 0.030301]

FW = 5,000*(38.71282)

FW = $193,564.10

The future worth of the quarterly withdrawal is $193,564.10

We calculate the amount left in the account after last withdrawal

Amount left in account = FW(monthly deposits) - FW(quarterly drawings)

Amount left in account = $255,509.10 - $193,564.10

Amount left in account = $61,945

Thus, the amount left in the account after last withdrawal is $61,945

6 0

2 years ago

Amy Xia's plant is designed to produce 10 comma 000 10,000 hammers per day but is limited to making 6 comma 000 6,000 hammers p

Sergio [31]

Answer:

60%

Explanation:

The computation of the utilization rate for the plant is shown below:

As we know that

Utilization rate = Actual output ÷ Design capacity

where

Actual output is 6,000 hammers per day

And, the design capacity is 10,000 hammers per day

So by considering the above information, the utilization rate is

= 6,000 hammers per day ÷ 10,000 hammers per day

= 60%

It is always expressed in a percentage form

6 0

3 years ago