51) 5x-1=0 and x+6=0
5x=1, x=1/5 and x=-6
2 solutions x=1/5 and x=-6
52)x(2x+3)=0
2x=0 and 2x+3 =0
x=0 and x=-3/2=-1.5
53) x(5x-1)=0
x=0 and 5x-1=0
x=0 and x=1/5
54) z(4z+7) =0
z=0 and 4z+7=0
z=0 and z= - 7/4 = -1.75
z=0 and z=-1.75
Given that there are 12 persons, the first choice may be in 12 different ways, the second choice may be in 11 different ways, ther third in 10 different ways, the fourth in 9 different ways and the fith in 8 different ways, for a total of:
12x11x10x9x8 different combinations.
Now you have to take in account that 5x4x3x2 are repetitions. So you have to divide the previos counting by 5x4x3x2.
(12x11x10x9x8)/(5x4x3x2) = 792 different subcommittees.
Also, you can use the formula for combinations: C(m,n) = m! / (n! (m-n)!)
C (12, 5) = 12! / (5!) (12-5)! = [12x11x10x9x8x7!] / [5! 7!] = [12x11x10x9x8]/[5x4x3x2] = 792
Answer: M= 14 or -14
Reason: When the absolute value symbol is around a number it turns it into it how far from 0 is it. And both 14 and -14 are 14 numbers away from 0
Hope this helps
The probability of selecting a solid chocolate piece followed by two cherry-filled chocolates, would be 27.387 or as rounded would be 27.4
Answer:
125.66
Step-by-step explanation:
C = 2πr = 2·π·20 = 125.66371
