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Advocard [28]
3 years ago
13

What is the vertex form, f(x) = a(x - h)2-k, for a parabola that passes through the point (2,8) and has (1,0) as its

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

Step-by-step explanation:

hello :

f(x) = a(x - h)²-k   ....vertex form  when the vertex is : (h,k)

h=1  and  k=0   so : f(x) = a(x-1)²

a parabola that passes through the point (2,8) : f(2)=8

a(2-1)² =8

a= 8

f(x) = 8(x-1)²=  8(x²-2x+1)

f(x) 8x²-16x+8   .....standard form

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Morgarella [4.7K]

An integer is a whole number, in other words, a number that isn't a fraction or decimal.

0 + 0 + -2 + -2 + 2 + -2 = -4

-4 is an integer because it is not a fraction or decimal.

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Answer:

1/2

Step-by-step explanation:

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Determine the slope of a line that goes through (2,7) and (11,10)
tia_tia [17]

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3 years ago
Write the equation of the line that passes through the points (-6, -9) and
e-lub [12.9K]

Answer:

y - 7 = 16/13(x - 7)

General Formulas and Concepts:

<u>Alg I</u>

Point-Slope Form: y - y₁ = m(x - x₁)  

  • x₁ - x coordinate
  • y₁ - y coordinate
  • m - slope

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-6, -9)

Point (7, 7)

<u>Step 2: Find slope </u><u><em>m</em></u>

  1. Substitute:                   m=\frac{7+9}{7+6}
  2. Add:                             m=\frac{16}{13}

<u>Step 3: Write equation</u>

y - 7 = 16/13(x - 7)

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3 years ago
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3 years ago
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