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Advocard [28]
3 years ago
13

What is the vertex form, f(x) = a(x - h)2-k, for a parabola that passes through the point (2,8) and has (1,0) as its

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer:

Step-by-step explanation:

hello :

f(x) = a(x - h)²-k   ....vertex form  when the vertex is : (h,k)

h=1  and  k=0   so : f(x) = a(x-1)²

a parabola that passes through the point (2,8) : f(2)=8

a(2-1)² =8

a= 8

f(x) = 8(x-1)²=  8(x²-2x+1)

f(x) 8x²-16x+8   .....standard form

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<h3>How to find the difference of the expression?</h3>

The difference of the expression can be found when we combine the like terms.

Therefore,

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)

6y⁴ + 3y² - 7  - 12y⁴ + y² - 5

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