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3 years ago

A photo is 8 cm long and 6 cm wide. It is enlarged to make a print that is 18 cm wide.

Mathematics

1 answer:

dezoksy [38]3 years ago

3 0

Answer:

24 cm

Step-by-step explanation:

The photo was 6 cm wide, and was made into 18 cm wide. Divide 18 with 6:

18/6 = 3

To solve for the length enlargement, multiply 3 with the length, or 8 cm:

8 x 3 = 24

24 cm is the length of the enlargement.

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For a population with an unknown distribution, the form of the sampling distribution of the sample mean is _____. Group of answe

Nesterboy [21]

For a population where the distribution is unknown, the sampling distribution of the sample mean will be b which is approximately normal for all sample sizes.

Given options regarding sample sizes.

We have to choose the correct option which shows the sample mean characteristics when the distribution is unknown.

Based on the central limit theorem the sampling distribution of the sample mean for either skewed variable ir normally distributed variable can be approximated given the mean and standard deviation.

The central limit theorem is said to be true when n greater than or equal to 30.

When n is greater than 30 ,z test is used, when n is less than 30 ,t test is used.

Hence for a population where the distribution is unknown ,the sampling distribution of the sample mean will be approximately normal for all sample sizes.

Learn more about sample at brainly.com/question/24466382

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Question is incomplete as it includes options in a right way:

1)exactly normal for large sample,

2) approximately normal for all sample sizes,

3) exactly normal for all sample sizes.

6 0

2 years ago

[PLEASE ANSWER BOTH QUESTIONS] The following data points represent the number of quesadillas each person at Toby's Tacos ate. So

Fynjy0 [20]

Answer:

Part 1: Already solved.

Part 2: 1 quesadilla.

Step-by-step explanation:

Part 1: The data points given are 0, 0, 1/4, 1/2, 1/2, 1, 1, 1, 5/4, 2, and 2.

The data are already sorted from least to greatest.

Part 2: To get the interquartile range, we must know the first and third quartiles. To find those, we need to know the median of the data.

There are 11 data points, so we can cross out 5 numbers on the left and cross out 5 numbers on the right. That leaves a median of 1.

Since we know the median is 1, we can find the first quartile by finding the median of the following numbers: 0, 0, 1/4, 1/2, 1/2 (any number less than 1). There are five numbers, so cross out two numbers from the left and cross out two numbers from the right. We are left with a first quartile of 1/4.

Now that we have the first quartile, we need to find the third quartile. Since the median was actually the first "1" in the data set, the third quartile will be the median of the numbers to the right of that "1": 1, 1, 5/4, 2, 2. Cross out the leftmost two numbers, and cross out the rightmost two numbers. We are left with a third quartile of 5/4.

Now that we have both the third and first quartiles, we can find the interquartile range! The IQR is calculated by finding the third quartile minus the first quartile. 5/4 - 1/4 = 4/4 = 1.

So, your interquartile range is 1 quesadilla.

Hope this helps!

5 0

4 years ago

Read 2 more answers

Approximately 5% of calculators coming out of the production lines have a defect. Fifty calculators are randomly selected from t

baherus [9]

Answer:

0.2611 = 26.11% probability that exactly 2 calculators are defective.

Step-by-step explanation:

For each calculator, there are only two possible outcomes. Either it is defective, or it is not. The probability of a calculator being defective is independent of any other calculator, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$