ar(ΔABO) = ar(ΔCDO)
Explanation:
The image attached below.
Given ABCD is a trapezoid with legs AB and CD.
AB and CD are non-parallel sides between the parallels AD and BC.
In ΔABD and ΔACD,
We know that, triangles lie between the same base and same parallels are equal in area.
⇒ AD is the common base for ΔABD and ΔACD and they are lie between the same parallels AD and BC.
Hence, ar(ΔABD) = ar(ΔACD) – – – – (1)
Now consider ΔABO and ΔCDO,
Subtract ar(ΔAOD) on both sides of (1), we get
ar(ΔABD) – ar(ΔAOD) = ar(ΔACD) – ar(ΔAOD)
⇒ar(ΔABO) = ar(ΔCDO)
Hence, ar(ΔABO) = ar(ΔCDO).
Answer:
x = 6 + 3√10
Step-by-step explanation:
Since this is an unfactorable expression, we need to apply the Quadratic Formula, <em>-</em><em>b</em><em> </em><em>±</em><em> </em><em>√</em><em>b</em><em>²</em><em> </em><em>-</em><em> </em><em>4ac</em><em>\</em><em>2a</em><em> </em>[radical wrapped around <em>b</em><em>²</em><em> </em><em>-</em><em> </em><em>4ac</em>]. Evaluate, then you will end up with the answer above.
I am joyous to assist you anytime.
The probability is (0.10 * 0.50 + 0.01 * 0.20 + 0.89 * 0.01) * 100% = 6.09%.
Answer: 9 1/3
Step-by-step explanation: There are four of them and, assuming there is no space in between them, they all take up the same amount of space. So that means, if they were added up, it’d be 2 1/3 +2 1/3 + 2 1/3 +2 1/3. That can be simplified to 4 x (2 + 1/3). When multiplied, it equals 8 + 4/3=8 + 1 +1/3=9 + 1/3=9 1/3.