Question

the diameter of a cylindrical construction pipe is 4 ft. if the pipe is 19 ft long, what s it’s volume?

Answer 1

Answer:

76$\pi$ or 238.76 $units^{3}$

Step-by-step explanation:

The volume of a cylinder is V = $\pi r^{2} h$

Here the radius is  r = $\frac{1}{2} d$ = $\frac{1}{2}(4)=2$

The height is given as 19 ft

Then plug in all the numbers into the equation

V = $\pi (2^{2})(19) = 76\pi = 238.76 units^{3}$