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LekaFEV [45]
3 years ago
7

How many feet is in 215 yards

Mathematics
2 answers:
Lilit [14]3 years ago
6 0
645 feet.

Explanation:
We know that are 3 feet in a yard, so let's set up a proportion to solve this

x215
3 feet n
-------- = -----------
1 yard 215 yards
x 215

We are solving for n. To get from 1 to 215, we multiply by 215. So to get from 3 to the answer, we must multiply by 215 as well. 3 x 215 = 645, therefore that is the answer.
emmainna [20.7K]3 years ago
4 0
There are 3 ft in a yard
So just multiply

3*215= 645

So there are 645 feet in 215 yard
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klemol [59]

The ages are consecutive even numbers.
The youngest child is  (x+3) years old.
Every even number is 2 more than the one before it.
So the three ages are

           (x + 3),  (x + 5),  and  (x + 7).

Their sum is    x+3  +  x+5  +  x+7  =  3x + 15

But we're told that their sum is  42, so we can write

                                              3x + 15 = 42  <== the equation

Subtract 15 from each side:  3x         =  27

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So the three ages are  12,  14,  and  16.

The oldest child is  16  years old.

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3 years ago
What is the supplement to an angle that measures 58 degrees? <br>a) 180<br>b)122<br>c)132<br>d)58​
skelet666 [1.2K]

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Step-by-step explanation:

Supplementary just means two angles sum to 180.

3 0
3 years ago
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The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

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Licemer1 [7]

give some Parameters so that we can solve

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ValentinkaMS [17]

Answer:

$60

Step-by-step explanation:

This is because 400 times 0.03 is 12 and 12 times 5 is 60

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