Answer:
the dimensions of the most economical shed are height = 10 ft and side 5 ft
Step-by-step explanation:
Given data
volume = 250 cubic feet
base costs = $4 per square foot
material for the roof costs = $6 per square foot
material for the sides costs = $2.50 per square foot
to find out
the dimensions of the most economical shed
solution
let us consider length of side x and height is h
so we can say x²h = 250
and h = 250 / x²
now cost of material = cost of base + cost top + cost 4 side
cost = x²(4) + x²(6) + 4xh (2.5)
cost = 10 x² + 10xh
put here h = 250 / x²
cost = 10 x² + 10x (250/ x² )
cost = 10 x² + (2500/ x )
differentiate and we get
c' = 20 x - 2500 / x²
put c' = 0 solve x
20 x - 2500 / x² = 0
x = 5
so we say one side is 5 ft base
and height is h = 250 / x²
h = 250 / 5²
height = 10 ft
The question is basically asking you how much area of the yard the pool takes up, in essence the area the pool takes up.
So we are going to find the area of the pool.
Area of pool is = pi x r^
= 3.14 x 7^2
= 153.86 ft^2
Therefore the pool takes up 153.86 ft^2 of space.
What alllll to be solved ????
Answer:
Step-by-step explanation:
It is given that, 
We need to find the value of 
As 
Solving LHS

Now comparing the coefficients of 
In LHS the coefficient of
is 25
In RHS the coefficient of
is 
It implies that, 
So, the value of
is 25.