Answer:
This one is also B my friend
Answer:
-4n + 5y + 6
Step-by-step explanation:
Distribute the negative
−4n + 5y + 6
There is really no answer for this but all you have to do is to multiply the figures outside the bracket by the ones inside the brackets.
Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
<h3>Given Equation:-</h3>

<h3>Step by step expansion:</h3>



























In the given diagram, we can note that the tree divides the hypotenuse of the triangle as well as the side where the tree is based into halves.
In a triangle, when a line is drawn joining between the midpoints of two sides, this line is always parallel to the third side and equals half its length.
Applying this concept to the given diagram here, we will find that the tree is joining the midpoints of two sides of the triangle. this means that the tree is parallel to the building and the height of the tree is half the height of the building.
Therefore:
height of tree = 0.5 * 120 = 60 ft