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3 years ago

A 2D vector can have a component equal to zero even when its magnitude is nonzero.

Mathematics

1 answer:

lys-0071 [83]3 years ago

5 0

Answer:

T F F F T F T

Step-by-step explanation:

A 2D vector can have a component equal to zero even when its magnitude is nonzero. TRUE.

it will be actually a 1d vector, but it's still a 2d vector too. this happens when the vector it's aligned to one of the axis.

The direction of a vector can be different in different coordinate systems. FALSE

The direction of a vector is independent of any coordinate system.

A 2D vector can have a magnitude equal to zero even when one of its components it nonzero. FALSE.

because the only way $\sqrt{x^{2} +y^{2} } =0$ is that both x and y are equal to zero

The magnitude of a vector can be different in different coordinate systems. FALSE.

The magnitude stays the same in every coordinate system

It is possible to multiply a vector by a scalar. TRUE.

it changes only it's magnitude.

It is possible to add a scalar to a vector. FALSE.

you can´t sum elements of diferent spaces. R, $R^{2}$ , etc

The components of a vector can be different in different coordinate systems.TRUE.

The components of a vector are just a way for identifying the vector, in a determinate coordinate system, the way i call those components will change as I change the name I call every point in the plane.

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Answer:

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2 years ago

An arch is in the shape of a parabola. It has a span of 100 feet and a maximum height of 25 ft.

faltersainse [42]

Answer:

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center is 24 feet

Step-by-step explanation:

An arch is in the shape of a parabola. It has a span of 100 feet, the vertex lies at the center 50 and the maximum height of 25 ft.

Vertex at (50,25)

vertex form of the equation is

$y=a(x-h)^2+k$ , (h,k) is the center

$y=a(x-50)^2+25$

the parabola starts at (0,0) that is (x,y)

$0=a(0-50)^2+25$

subtract 25 from both sides

$-25=a(-50)^2$

$-25=a(2500)$

divide both sides by 2500

$a=-\frac{1}{100}$

$y=-\frac{1}{100}(x-50)^2+25$

the height of the arch 10 feet from the center.

center is at 50, 10 feet from the center so x=40 and x=60

$y=-\frac{1}{100}(40-50)^2+25$

y=24

the height of the arch 10 feet from the center is 24 feet

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GIVING BRAINIEST!!!!!!!!

Sav [38]

Answer:

look at the horizontal line in the picture. the degree measure of any line is 180° given there's a perpendicular ray through that horizontal line it's therfore split into two sides both with angle measure of 90°.

given f is 71° then g can be found knowing that both g and f must add to 90°. 71+g=90. g=19°

now look at f again. f and d are what's known as vertical angles and that means that they're angle measures are congruent. therfore the measure of d is 71° d=71°

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aunaitituitmg our information we know 71+e=180 then e must equal 109° e=109°

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