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jeka94
3 years ago
11

Evaluate the following expression when x=14. X^2+5x+11

Mathematics
2 answers:
Effectus [21]3 years ago
7 0

Start by substituting 14 in for x everywhere that x appears in the problem.

So we have (14)² + 5(14) + 11.

Remember that PEMDAS tells you to deal

with your exponents before multiplying.

So you must square the 14 to get 196.

So we have 196 + 5(14) + 11.

Now multiply 5(14) to get 70.

So we have 196 + 70 + 11.

Now we can simply add to get 277.

NikAS [45]3 years ago
6 0

Answer:

277

Step-by-step explanation:

14^2+5(14)+11=

196+70+11=

277

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Alright...simple...showing all steps.. ;)

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2x+y=7
and
3x+5y=14

To be able to even solve for any of the variables...multiply the equations by...2...and..3...

2x+y=7----*3--> 6x+3y=21
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=========

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