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pshichka [43]
4 years ago
14

Simplify, write each answer in scientific notation (7.4 x 10)^2

Mathematics
1 answer:
telo118 [61]4 years ago
4 0
Your answer is 5.476 x 10^3
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Help me please urgent
motikmotik

Answer:

option B, option D

Step-by-step explanation:

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7 0
3 years ago
Solve for x: 3(x + 1) = −2(x − 1) + 6
finlep [7]
<span>3(x + 1) = −2(x − 1) + 6
3x + 3 = -2x + 2 + 6
5x = 5
x = 1

answer
x = 1</span>
8 0
3 years ago
Read 2 more answers
Write the expression in WORDS!<br><br> 5x + 3
Svet_ta [14]
The expression 5x+3 would be three more than five times a number! More than in this case would be addition - so if you get the same problem with subtraction you just change more to less!
Basically what it's tell you is that if x stood for 2 in this case 5*2 = 10 since it's 3 MORE than 5 times a number (x is in place of a number), you're adding 3 to 10 and that gives you 13!
I hope I simplified it a little more and you understand!
Good luck, rockstar! c: I hope this helped!
8 0
3 years ago
I need help with this.. Anybodyyy??!
Marta_Voda [28]

Step-by-step explanation:

Given

c² = a² + b²

Making a² subject then

a² = c² - b²

Hope it will help :)

4 0
3 years ago
In this problem, x = c1 cos t + c2 sin t is a two-parameter family of solutions of the second-order de x'' + x = 0. find a solut
nordsb [41]

If you are already given the general solution, finding the particular solution means to impose some conditions in order to fix the coefficients of the general solution.

The first thing we need to impose is that the function must output -1 when the input is zero. So, if we plug zero as input we have

x(t) = c_1 \cos(t) + c_2 \sin(t) \implies x(0) = c_1 \cos(0) + c_2 \sin(0) = c_1

But we want x(0)=-1, which implies x(0)=c_1=-1

So, we fixed the first coefficient. To fix the second one, we can use the second piece of information (and of course the already-found value for c_1).

We want the first derivative to output 3 when the input is zero. So, first of all, let's compute the first derivative, and evaluate it in zero:

x(t) = -\cos(t) + c_2 \sin(t) \implies x'(t) = \sin(t) + c_2\cos(t)

x'(0) = \sin(0) + c_2\cos(0) = c_2

And as before, since x'(0)=c_2 and we want x'(0)=3, we deduce c_2=3.

So, once we fix both coefficients, the general solution becomes

x(t) = c_1 \cos(t) + c_2 \sin(t) \mapsto -\cos(t)+3\sin(t)

3 0
3 years ago
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