Well, to find out whether she spent more time getting dressed or eating breakfast, we simply have to compare the fractions of the hour that she took on each.
We know that she took 3/6 of an hour to get dressed and 1/4 of an hour to eat breakfast. To find out which activity she spent more time on, we simply need to see which fraction is bigger.
To do this, we must first reduce the fractions to lowest terms. 1/4 is already in lowest terms, so we can leave that alone. 3/6 can be reduced, however, and since 3 goes into 6 twice, it reduces to 1/2.
Now, we can compare the fractions.
Is 1/2 of an hour or 1/4 of an hour more?
The answer is 1/2, so now we know that Bailey spent more time getting dressed than eating breakfast.
Hope that helped! =)
If y = xⁿ
∫y dx = xⁿ⁺¹ / (n + 1) + C Provided n ≠ -1.
y = √x
y = x^(0.5)
∫y dx = x^(0.5+1) / (0.5 + 1) = x^(1.5) / 1.5 = x^(1.5) / (3/2)
∫y dx = (2/3) x^(1.5) + C.
∫y dx = (2/3) x^(3/2) + C.
∫y dx = (2/3)√x³ + C
