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andrezito [222]
1 year ago
9

The x-intercepts of cosine become what for the secant function?

Mathematics
1 answer:
Anuta_ua [19.1K]1 year ago
8 0

using the definition of secant we know that,

sec(x)=\frac{1}{cos(x)}

then, the definition of x-intercept is that the function evaluated is equal to 0 then, if f(x) is equal to cos(x)

f(x)=cos(x)

we can say that if the function is equal to 0 then the function secant will look something like this

\begin{gathered} sec(x)=\frac{1}{0} \\  \end{gathered}

and we know that any number divided by 0 is undefined, so the x.intercepts make the function secant undefined, meaning that the x-intercepts become vertical asymptotes in the secant function.

Answer:

The x-intercepts of the function cosine become the vertical asymptotes of the secant function.

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Can someone explain this step by step? I'm very confused on how to solve it. Thanks!
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I will show each step algebraically. If you need further explanation, feel free to ask questions :)

\frac{x}{2} +7=3\\                     Rewrite

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Write the equation of the line that passes through the points (-9, -8) and (–6,6).
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<u><em>Explanation:-</em></u>

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Slope - intercept form  y= mx +C

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2 years ago
Is the function f(x) increasing or decreasing over the interval -2&lt; x&lt;-1 ?
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