SinB = cosC = AC / BC = 8/10 = 4/5;
tgB = ctg C = AC/AB = 8/6 = 4/3, because we use T. Pitagora for calculating AB;
sinC = cosB = AB/ BC = 6/10 = 3/5;
tgC = ctgB = AB/ AC = 6/8 = 3/4.
Valid because 3 x 3 is 9 :))
Answer:
log_4(256)=4
log_4(1/1024)=-5
log_4(16)=2
log_4(1/256)=-4
Step-by-step explanation:
We want to write a number, x, such that
Log_4(y)=x.
In exponential form that is 4^x=y.
So first number is x=4.
4^4=256 which means log_4(256) is 4 as a logarithm with base 4.
The second number is x=-5.
4^-5=1/4^5=1/1024 which means log_4(1/1024) is -5 as a logarithm with base 4.
The third number is x=2.
4^2=16 so log_4(16) is 2 as a logarithm with base 4.
The fourth number is x=-4.
Since 4^4=256 then 4^-4=1/256 which means -4 as a logarithm with base 4 is log_4(1/256).
So if it’s 2/12 it would be 1 flaw in every 6 light bulbs. so if there were 18 light bulbs there would be 3 flaws (6 * 3 is 18)
Answer:
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