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Fed [463]
3 years ago
5

Bart’s Boats: $4 for a life jacket rental

Mathematics
1 answer:
MissTica3 years ago
8 0

Answer: y=5x + 4 and y=6x

Step-by-step explanation:

for barts boat 4 is a set amount for a life jacket plus 5 per hour (5x)

bike land has no set amount for life jacket but has 6 dollars per hour (6x) :

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Find the volume of the solid under the surface z = 5x + 9y 2 and above the region bounded by x = y 2 and x = y 3.
Yanka [14]
Call the region in the x-y plane, bounded by x=y^2 and x=y^3, \mathcal D. Then the volume under the given surface is

\displaystyle\iint_{\mathcal D}(5x+9y)\,\mathrm dA=\int_{y=0}^{y=1}\int_{x=y^3}^{x=y^2}(5x+9y)\,\mathrm dx\,\mathrm dy=\frac{83}{140}
8 0
3 years ago
How much does 4 7/5 kg of candy cost if 5/6 kg costs 7.50
inn [45]

Answer:

$48.60

Step-by-step explanation:

4 7/5 is a funny way to express a fraction... but anway..... if this is correct, then the answer is as follows:

5/6 kg ------> cost $7.50

1 kg ----> costs $7.50 ÷ 5/6 kg = $9

4 7/5 kg ------> costs $9 x (4 7/5) = $9 x (27/5) = $48.60

3 0
3 years ago
Read 2 more answers
If d(x)=9x^2 and g(x)=5x+7 then d(x)-g(x) can be rewritten as
Angelina_Jolie [31]

Answer:

9x^2-5x-7

Step-by-step explanation:

d(x)=9x^2\\g(x)=5x+7\\d(x)-g(x)=\\(9x^2)-(5x+7)=\\9x^2-5x-7

Hope this helps!

7 0
3 years ago
Read 2 more answers
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
Dave uses 5 gallons of gas to drive 140 miles on the highway. If he travels at the same rate, how many miles can he drive on 7 g
Solnce55 [7]

Answer:

168 miles

Step-by-step explanation:

If he uses 5 gallons to drive 140 miles, that means that he can drive 24 miles for every gallon (140/5=24)

7 times 24 is 168 so he can drive 168 miles on 7 gallons of gas

5 0
3 years ago
Read 2 more answers
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