Answer:
y=x^2-2x+1 is matched to the second graph
Y=x^2-2x is matched to the third graph
Y=2x^2+4 is matched to the first graph
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
Answer:
m<B is 48°
Step-by-step explanation:
m<C is already 90°
m<A is 42°
42+90+x=180
132+x=180
x=48°
Answer:
y = 2x+3
Step-by-step explanation:
You can see that the line crosses the y-axis at (0,3), so the y-intercept is 3.
To find the slope, compare the coordinates of the two points marked on the line, (0,3) and (-3,-3).
slope = Δy/Δx = ((-3)-3)/((-3)-0) = (-6)/(-3) = 2
Slope-intercept equation for line of slope 2 and y-intercept 3:
y = 2x+3
